Algebraic Geometry and Number Theory: In Honor of Vladimir by Alex Eskin, Andrei Okounkov (auth.), Victor Ginzburg (eds.)

By Alex Eskin, Andrei Okounkov (auth.), Victor Ginzburg (eds.)

One of the main artistic mathematicians of our instances, Vladimir Drinfeld bought the Fields Medal in 1990 for his groundbreaking contributions to the Langlands software and to the speculation of quantum groups.

These ten unique articles via fashionable mathematicians, devoted to Drinfeld at the social gathering of his fiftieth birthday, extensively mirror the diversity of Drinfeld's personal pursuits in algebra, algebraic geometry, and quantity theory.

Contributors: A. Eskin, V.V. Fock, E. Frenkel, D. Gaitsgory, V. Ginzburg, A.B. Goncharov, E. Hrushovski, Y. Ihara, D. Kazhdan, M. Kisin, I. Krichever, G. Laumon, Yu.I. Manin, A. Okounkov, V. Schechtman, and M.A. Tsfasman.

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Extra info for Algebraic Geometry and Number Theory: In Honor of Vladimir Drinfeld’s 50th Birthday

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54 18 54 4 16 1 3 1 1 1 1 25 p¯ 1 + p¯ 1 p¯ 2 − p¯ 1 p1 + p¯ 3 − p2 + p¯ 1 . = 30 10 2 15 2 24 1 4 1 2 1 2 2 25 2 1 p¯ 1 − p¯ 1 p¯ 2 − p¯ 1 p1 + p¯ 3 p¯ 1 + p¯ 1 + p¯ 22 =− 360 60 12 45 36 40 1 5 2 1 1 25 25 − p¯ 2 p1 + p1 + p¯ 4 − p3 + p¯ 2 − p1 . 12 8 60 2 36 12 1 2 1 1 = − p¯ 1 + p¯ 2 + . 24 12 96 1 3 1 1 2 3 p¯ − p¯ 1 p¯ 2 − p¯ 1 p1 + p¯ 3 + p¯ 1 . = 108 1 36 4 27 8 1 4 1 2 1 1 9 1 p¯ 1 − p¯ 1 p1 + p¯ 3 p¯ 1 − p2 p¯ 1 + p¯ 21 − p¯ 22 = 216 12 108 8 32 72 1 1 2 1 9 3 9 − p¯ 2 p1 + p1 + p¯ 4 + p¯ 2 − p1 + .

N. This is obtained by computing the difference of residues using ϑ (1) = 1. 2 There are two obstacles to literally applying this lemma to the evaluation of (34). The first is the square roots in (34). However, we are ultimately interested in the expansion of (34) about xi = ±1. The expansion of the integrand about xi = ±1 contains no square roots, only the theta function and its derivatives. Formulas for integrating derivatives can be obtained from (35) by differentiating with respect to parameters.

N. This is obtained by computing the difference of residues using ϑ (1) = 1. 2 There are two obstacles to literally applying this lemma to the evaluation of (34). The first is the square roots in (34). However, we are ultimately interested in the expansion of (34) about xi = ±1. The expansion of the integrand about xi = ±1 contains no square roots, only the theta function and its derivatives. Formulas for integrating derivatives can be obtained from (35) by differentiating with respect to parameters.

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